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What will be the output of following Python code snippet?str1="012"num1=2num2=0for i in range(4): num1+=2 for j in range(len(str1)): num2=num2+num1num3=num2%int(str1)print(num3)7Infinite Loop0Error

Question

What will be the output of following Python code snippet?str1="012"num1=2num2=0for i in range(4): num1+=2 for j in range(len(str1)): num2=num2+num1num3=num2%int(str1)print(num3)7Infinite Loop0Error

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Solution

The provided Python code snippet is not correctly formatted, which makes it difficult to understand and predict the output. However, I'll try to interpret it as best as I can:

str1="012"
num1=2
num2=0
for i in range(4):
    num1+=2
    for j in range(len(str1)):
        num2=num2+num1
num3=num2%int(str1)
print(num3)

This code will result in a ValueError because it tries to convert the string "012" to an integer using the int() function. In Python, a string that starts with a "0" is considered to be in octal (base 8) format, but "8" and "9" are not valid digits in base 8, so "012" is not a valid octal number. Therefore, int("012") will raise a ValueError.

This problem has been solved

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