The output of the given code will be an infinite loop. This is because the outer loop variable 'i' is not being incremented within the loop. As a result, the condition for the outer loop (i

Question

The output of the given code will be an infinite loop. This is because the outer loop variable 'i' is not being incremented within the loop. As a result, the condition for the outer loop (i<3) will always be true, causing the loop to run indefinitely.

To fix this, you should increment 'i' within the outer loop. Here's how you can do it:

```python
i=0
while(i<3):    
    j=0    
    while(j<3):        
        print(i,j,end=" ")        
        j+=1    
    print()
    i+=1
```

With this correction, the output will be:

```
0 0 0 1 0 2 
1 0 1 1 1 2 
2 0 2 1 2 2 
```

Knowee AI · Accepted Answer

The output of the given code will be an infinite loop. This is because the outer loop variable 'i' is not being incremented within the loop. As a result, the condition for the outer loop (i<3) will always be true, causing the loop to run indefinitely.

To fix this, you should increment 'i' within the outer loop. Here's how you can do it:

```python
i=0
while(i<3):    
    j=0    
    while(j<3):        
        print(i,j,end=" ")        
        j+=1    
    print()
    i+=1
```

With this correction, the output will be:

```
0 0 0 1 0 2 
1 0 1 1 1 2 
2 0 2 1 2 2 
```

What will be the output for the following code?i=0while(i<3): j=0 while(j<3): print(i,j,end=" ") j+=1 print()0 00 10 20 0 0 0 1 2Infinite loopError

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