Given a string, , consisting of alphabets and digits, find the frequency of each digit in the given string.

Sure, here is a Python solution for your problem:

def digit_frequency(s):
    # Initialize a dictionary to store the frequency of each digit
    freq = {str(i): 0 for i in range(10)}

    # Iterate over each character in the string
    for char in s:
        # If the character is a digit, increment its frequency in the dictionary
        if char.isdigit():
            freq[char] += 1

    # Return the frequency dictionary
    return freq

# Test the function
s = "a11472o5t6"
print(digit_frequency(s))

In this code, we first initialize a dictionary freq with keys as string representations of digits from 0 to 9 and values as 0. Then we iterate over each character in the input string s. If the character is a digit (checked using the isdigit() method), we increment its count in the freq dictionary. Finally, we return the freq dictionary which contains the frequency of each digit in the string.

When you run this code with s = "a11472o5t6", it will print the frequency of each digit in the string.