Find the frequency of each digit from the given numberInput Format:Accept an integer value as inputOutput Format:Occurence of each digit as follows: 0 occurs  OCCURENCE_COUNT times 1 occurs  OCCURENCE_COUNT times 2 occurs  OCCURENCE_COUNT times ... 9 occurs  OCCURENCE_COUNT times

Sure, here is a step by step guide on how to solve this problem:

Step 1: Accept the integer input from the user. Let's call this input num.

Step 2: Convert the integer to a string. This can be done using the str() function in Python. Let's call this string num_str.

Step 3: Initialize a dictionary to store the frequency count of each digit. Let's call this dictionary digit_count. The keys of this dictionary will be the digits (0-9) and the values will be the frequency count of each digit.

Step 4: Iterate over each character (digit) in num_str. For each digit, if it is already a key in digit_count, increment its value by 1. If it is not a key in digit_count, add it to the dictionary with a value of 1.

Step 5: After the iteration, digit_count will contain the frequency count of each digit in num.

Step 6: Print the frequency count of each digit in the required format. You can do this by iterating over the keys of digit_count and printing the key and its corresponding value.

Here is a Python code snippet that implements the above steps:

num = int(input("Enter a number: "))
num_str = str(num)

digit_count = {str(i): 0 for i in range(10)}

for digit in num_str:
    digit_count[digit] += 1

for digit, count in digit_count.items():
    print(f"{digit} occurs {count} times")

This code will print the frequency count of each digit in the input number in the required format.