What is the output of the following program?t = 1while True:  if t%2 == 0:    break  print(t)  t + = 1Options1No Output12

The output of the given program will be 1.

Here's the step by step explanation:

1. The variable t is initialized with the value 1.
2. The while True: loop starts, which will run indefinitely until a break statement is encountered.
3. Inside the loop, the if condition checks if t is divisible by 2 (t%2 == 0). If it is, the break statement will be executed, and the loop will be terminated.
4. However, since t is 1 at the start, the if condition is not satisfied (since 1 is not divisible by 2), so the break statement is not executed.
5. The print(t) statement is then executed, which prints the current value of t, which is 1.
6. The t += 1 statement is then executed, which increments the value of t by 1. Now t is 2.
7. The loop then starts again from the beginning. This time, the if condition is satisfied (since 2 is divisible by 2), so the break statement is executed, and the loop is terminated.
8. Since the loop has been terminated, no more values of t are printed, so the final output of the program is just 1.