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Z is a standard normal random variable. The P(-1.5 <z < 1.09) equalsGroup of answer choices0.79530.07110.43220.3621

Question

Z is a standard normal random variable. The P(-1.5 <z < 1.09) equalsGroup of answer choices0.79530.07110.43220.3621

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Solution

The question is asking for the probability that a standard normal random variable Z falls between -1.5 and 1.09.

Step 1: Understand the standard normal distribution A standard normal distribution is a normal distribution with a mean of 0 and a standard deviation of 1. The variable Z represents the number of standard deviations away from the mean a data point is.

Step 2: Use the Z-table A Z-table, also known as the standard normal table, is used to find the area under the curve for a standard normal distribution. The area under the curve represents the probability.

Step 3: Find the probabilities The Z-table gives the probability that Z is less than a given value. So, to find P(-1.5 < Z < 1.09), we need to find P(Z < 1.09) and P(Z < -1.5), and then subtract the two.

Looking up 1.09 in the Z-table gives a probability of 0.8621, meaning there's an 86.21% chance that Z is less than 1.09.

Looking up -1.5 in the Z-table gives a probability of 0.0668, meaning there's a 6.68% chance that Z is less than -1.5.

Step 4: Subtract the probabilities Subtract P(Z < -1.5) from P(Z < 1.09) to get P(-1.5 < Z < 1.09):

0.8621 - 0.0668 = 0.7953

So, P(-1.5 < Z < 1.09) = 0.7953.

Therefore, the correct answer is 0.7953.

This problem has been solved

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