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Given that z is a standard normal random variable, compute the following probabilities.P(-2.5 < z)Question 5Select one:a.0.9938b.0.0622c.0.0062d.0.9928

Question

Given that z is a standard normal random variable, compute the following probabilities.P(-2.5 < z)Question 5Select one:a.0.9938b.0.0622c.0.0062d.0.9928

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Solution

To solve this problem, we need to use the standard normal distribution table (also known as the Z-table).

The standard normal distribution table gives the probability that a standard normal random variable Z is less than or equal to a given value z. In other words, it gives P(Z ≤ z).

The question asks for P(-2.5 < z), which is the same as 1 - P(Z ≤ -2.5).

Looking up -2.5 in the Z-table, we find that P(Z ≤ -2.5) = 0.0062.

Therefore, P(-2.5 < z) = 1 - P(Z ≤ -2.5) = 1 - 0.0062 = 0.9938.

So, the answer is a. 0.9938.

This problem has been solved

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