Z is a standard normal random variable. The P(-1.5 <z < 1.09) equalsGroup of answer choices0.43220.36210.79530.0711

To solve this problem, we need to find the probability that a standard normal random variable Z falls between -1.5 and 1.09.

Step 1: We need to find the Z-scores for -1.5 and 1.09. Since Z is a standard normal random variable, the Z-scores are simply -1.5 and 1.09.

Step 2: We need to find the probabilities associated with these Z-scores. We can do this by looking up the Z-scores in a standard normal distribution table or using a calculator with a normal distribution function.

Step 3: The probability that Z is less than -1.5 is found by looking up -1.5 in the Z-table. The value is 0.0668. This means that there is a 6.68% chance that Z is less than -1.5.

Step 4: The probability that Z is less than 1.09 is found by looking up 1.09 in the Z-table. The value is 0.8621. This means that there is a 86.21% chance that Z is less than 1.09.

Step 5: To find the probability that Z falls between -1.5 and 1.09, we subtract the probability that Z is less than -1.5 from the probability that Z is less than 1.09.

So, P(-1.5 < Z < 1.09) = P(Z < 1.09) - P(Z < -1.5) = 0.8621 - 0.0668 = 0.7953.

So, the answer is 0.7953.