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What is the output after this code is compiled and its executable run?#include <iostream>using namespace std;int main(){ for( int n = 10; n > 0; n-- ){ if( n == 5 ) continue; cout << n << ", "; } cout << "\n"; return 0;}Select one:a.10, 9, 8, 7, 6, 4, 3, 2b.10, 9, 8, 7, 6, 4, 3, 2,c.10, 9, 8, 7, 6, 4, 3, 2, 1d.10, 9, 8, 7, 6, 4, 3, 2, 1,

Question

What is the output after this code is compiled and its executable run?#include <iostream>using namespace std;int main(){ for( int n = 10; n > 0; n-- ){ if( n == 5 ) continue; cout << n << ", "; } cout << "\n"; return 0;}Select one:a.10, 9, 8, 7, 6, 4, 3, 2b.10, 9, 8, 7, 6, 4, 3, 2,c.10, 9, 8, 7, 6, 4, 3, 2, 1d.10, 9, 8, 7, 6, 4, 3, 2, 1,

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Solution

The correct answer is c. 10, 9, 8, 7, 6, 4, 3, 2, 1. This is because the code is a loop that starts at 10 and decrements by 1 each time. However, when the loop reaches 5, the 'continue' statement is executed, which skips the rest of the loop for that iteration. Therefore, 5 is not printed, and the loop continues with 4.

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What is the output after the following code is compiled and its executable run?#include <iostream>using namespace std;int main(){ int a, b, c; a = 5; b = 6; c = (a>b) ? a : b; cout << c << "\n"; return 0;}Select one:a.1b.5c.6d.11

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What is the output after this code is compiled and its executable run?#include <iostream>using namespace std;int main(){ for( int n = 10; n > 0; n-- ){ if( n == 5 ) continue; cout << n << ", "; } cout << "\n"; return 0;}Select one:a.10, 9, 8, 7, 6, 4, 3, 2b.10, 9, 8, 7, 6, 4, 3, 2,c.10, 9, 8, 7, 6, 4, 3, 2, 1d.10, 9, 8, 7, 6, 4, 3, 2, 1,

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