Find the solution of the system of equations.8, x, plus, 4, y, equals, minus, 248x+4y=−24minus, 5, x, plus, 4, y, equals, minus, 11−5x+4y=−11
Question
Find the solution of the system of equations.8, x, plus, 4, y, equals, minus, 248x+4y=−24minus, 5, x, plus, 4, y, equals, minus, 11−5x+4y=−11
Solution
The system of equations is:
- 8x + 4y = -24
- -5x + 4y = -11
Let's solve it step by step:
Step 1: Simplify the equations if possible. In this case, we can divide the first equation by 4:
2x + y = -6
So, the simplified system of equations is:
2x + y = -6 -5x + 4y = -11
Step 2: Multiply the equations by necessary multiples such that the coefficients of y's in both equations will cancel out each other when one equation is subtracted from the other. In this case, multiply the first equation by 4 and the second equation by 1:
8x + 4y = -24 -5x + 4y = -11
Step 3: Subtract the second equation from the first:
8x - (-5x) = 13x -24 - (-11) = -13
So, the value of x is x = -13/13 = -1.
Step 4: Substitute x = -1 into the first equation:
2*(-1) + y = -6 -2 + y = -6 y = -6 + 2 = -4
So, the solution to the system of equations is x = -1, y = -4.
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