Find the solution of the system of equations.minus, 6, x, plus, 5, y, equals, 34−6x+5y=34minus, 6, x, minus, 10, y, equals, 4−6x−10y=4
Question
Find the solution of the system of equations.minus, 6, x, plus, 5, y, equals, 34−6x+5y=34minus, 6, x, minus, 10, y, equals, 4−6x−10y=4
Solution 1
To solve the system of equations:
-6x + 5y = 34 -6x - 10y = 4
We can use the method of substitution or elimination. Here, we will use the elimination method since the coefficients of x in both equations are the same.
Step 1: Align the equations:
-6x + 5y = 34 -6x - 10y = 4
Step 2: Subtract the second equation from the first:
(-6x + 5y) - (-6x - 10y) = 34 - 4
This simplifies to:
15y = 30
Step 3: Solve for y:
y = 30 / 15 = 2
Step 4: Substitute y = 2 into the first equation:
-6x + 5(2) = 34 -6x + 10 = 34 -6x = 24 x = 24 / -6 = -4
So, the solution to the system of equations is x = -4, y = 2.
Solution 2
To solve the system of equations:
-6x + 5y = 34 -6x - 10y = 4
We can use the method of substitution or elimination. Here, we will use the elimination method.
Step 1: Align the equations
-6x + 5y = 34 -6x - 10y = 4
Step 2: Subtract the second equation from the first
This will eliminate x.
(5y - (-10y)) = (34 - 4)
Step 3: Solve for y
15y = 30 y = 30 / 15 y = 2
Step 4: Substitute y = 2 into the first equation
-6x + 5(2) = 34 -6x + 10 = 34 -6x = 24 x = 24 / -6 x = -4
So, the solution to the system of equations is x = -4 and y = 2.
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