Which shows the equation below written in standard form?9 - 7x = (4x - 3)2 + 5A.16x2 - 17x - 5 = 0B.16x2 - 17x + 5 = 0C.16x2 - 31x + 5 = 0D.16x2 - 31x - 5 = 0SUBMITarrow_backPREVIOUS

To solve this problem, we first need to expand the right side of the equation.

The equation is: 9 - 7x = (4x - 3)^2 + 5

First, expand (4x - 3)^2. This is the same as (4x - 3) * (4x - 3), which equals 16x^2 - 24x + 9.

So, the equation now is: 9 - 7x = 16x^2 - 24x + 9 + 5

Simplify the right side of the equation: 9 - 7x = 16x^2 - 24x + 14

Next, we want to set the equation to equal zero, so we subtract (9 - 7x) from both sides: 0 = 16x^2 - 24x + 14 - 9 + 7x

Simplify the equation: 0 = 16x^2 - 17x + 5

So, the equation in standard form is 16x^2 - 17x + 5 = 0.

Therefore, the answer is B. 16x^2 - 17x + 5 = 0.