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Which shows the equation below written in the form ax2 + bx + c = 0?2x2 - 3 = -6x - 2A.2x2 - 6x - 1 = 0B.2x2 + 6x - 1 = 0C.2x2 + 6x - 5 = 0D.2x2 - 6x - 5 = 0SUBMITarrow_backPREVIOUS

Question

Which shows the equation below written in the form ax2 + bx + c = 0?2x2 - 3 = -6x - 2A.2x2 - 6x - 1 = 0B.2x2 + 6x - 1 = 0C.2x2 + 6x - 5 = 0D.2x2 - 6x - 5 = 0SUBMITarrow_backPREVIOUS

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Solution

The equation given is 2x^2 - 3 = -6x - 2.

To write it in the form ax^2 + bx + c = 0, we need to move all terms to one side of the equation.

We can do this by adding 6x and 2 to both sides of the equation.

Doing this gives us:

2x^2 + 6x - 3 + 2 = 0

Simplifying the equation gives us:

2x^2 + 6x - 1 = 0

So, the answer is A. 2x^2 - 6x - 1 = 0.

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