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What will be the output of the following Java code? class codetantra  {    public static void main(String args[])     {      char a = 'A';      char b = 76;      b++;      a++;      System.out.println(a + " " + b);    }   }OptionsC NB MD OA M

Question

What will be the output of the following Java code? class codetantra  {    public static void main(String args[])     {      char a = 'A';      char b = 76;      b++;      a++;      System.out.println(a + " " + b);    }   }OptionsC NB MD OA M

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Solution

The output of the given Java code will be 'B' 'M'.

Here's the step by step explanation:

  1. The variable 'a' is initialized with the character 'A'.
  2. The variable 'b' is initialized with the integer 76, which corresponds to the ASCII value of the character 'L'.
  3. The '++' operator is used to increment the values of 'a' and 'b'. This means 'a' becomes 'B' (since 'B' is the next character after 'A') and 'b' becomes 'M' (since 'M' is the character corresponding to the ASCII value 77, which is one more than 76).
  4. The System.out.println statement prints the values of 'a' and 'b', separated by a space.

So, the output will be 'B' 'M'.

This problem has been solved

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