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ct the correct answerWhat will be the output of the following Java code? class codetantra  {    public static void main(String args[])     {      char a = 'A';      char b = 76;      b++;      a++;      System.out.println(a + " " + b);    }   }

Question

ct the correct answerWhat will be the output of the following Java code? class codetantra  {    public static void main(String args[])     {      char a = 'A';      char b = 76;      b++;      a++;      System.out.println(a + " " + b);    }   }

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Solution

The output of the Java code will be "B 77".

Here's the step by step explanation:

  1. The variable 'a' is initialized with the character 'A'. The ASCII value of 'A' is 65.

  2. The variable 'b' is initialized with the number 76. In ASCII, 76 corresponds to the character 'L'.

  3. The 'b++' operation increments the value of 'b' by 1, so 'b' now holds the value 77. In ASCII, 77 corresponds to the character 'M'.

  4. The 'a++' operation increments the value of 'a' by 1, so 'a' now holds the character 'B' (since 'B' is the next character after 'A' in the ASCII table).

  5. The 'System.out.println(a + " " + b);' statement prints the values of 'a' and 'b', separated by a space. Since 'a' holds 'B' and 'b' holds 77, the output is "B 77".

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