The question seems to be incomplete. The number of photoelectrons emitted by the sphere before emission stops depends on the total energy supplied by the source of light, which is not provided in the question.

However, I can guide you on how to calculate the number of photoelectrons once you have the total energy.

1. First, you need to calculate the energy required to emit one photoelectron. This is given by the difference between the energy of the incident photon and the work function of the metal. In this case, it is 4.2 eV - 1.5 eV = 2.7 eV.

2. Convert this energy to Joules by multiplying by the charge of an electron (1.6 x 10^-19 C). So, 2.7 eV = 2.7 * 1.6 x 10^-19 = 4.32 x 10^-19 Joules.

3. Now, divide the total energy supplied by the source of light (in Joules) by the energy required to emit one photoelectron (in Joules). This will give you the total number of photoelectrons that can be emitted before the emission stops.

Remember, this calculation assumes that every incident photon results in the emission of a photoelectron, which is not always the case in reality.

Question

The question seems to be incomplete. The number of photoelectrons emitted by the sphere before emission stops depends on the total energy supplied by the source of light, which is not provided in the question.

However, I can guide you on how to calculate the number of photoelectrons once you have the total energy.

1. First, you need to calculate the energy required to emit one photoelectron. This is given by the difference between the energy of the incident photon and the work function of the metal. In this case, it is 4.2 eV - 1.5 eV = 2.7 eV.

2. Convert this energy to Joules by multiplying by the charge of an electron (1.6 x 10^-19 C). So, 2.7 eV = 2.7 * 1.6 x 10^-19 = 4.32 x 10^-19 Joules.

3. Now, divide the total energy supplied by the source of light (in Joules) by the energy required to emit one photoelectron (in Joules). This will give you the total number of photoelectrons that can be emitted before the emission stops.

Remember, this calculation assumes that every incident photon results in the emission of a photoelectron, which is not always the case in reality.

Knowee AI · Accepted Answer

The question seems to be incomplete. The number of photoelectrons emitted by the sphere before emission stops depends on the total energy supplied by the source of light, which is not provided in the question.

However, I can guide you on how to calculate the number of photoelectrons once you have the total energy.

1. First, you need to calculate the energy required to emit one photoelectron. This is given by the difference between the energy of the incident photon and the work function of the metal. In this case, it is 4.2 eV - 1.5 eV = 2.7 eV.

2. Convert this energy to Joules by multiplying by the charge of an electron (1.6 x 10^-19 C). So, 2.7 eV = 2.7 * 1.6 x 10^-19 = 4.32 x 10^-19 Joules.

3. Now, divide the total energy supplied by the source of light (in Joules) by the energy required to emit one photoelectron (in Joules). This will give you the total number of photoelectrons that can be emitted before the emission stops.

Remember, this calculation assumes that every incident photon results in the emission of a photoelectron, which is not always the case in reality.

A source of light is placed above a sphere of radius 10cm. How many photoelectrons must be emitted by the sphere before emission of photoelectrons stops? The energy of incident photon is 4.2 eV and the work function of the metal is 1.5 eV.

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