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The maximum kinetic energy of photoelectrons emitted from a surface when photons of energy 6 eV fall on it is 4 eV. The stopping potential in volts is :

Question

The maximum kinetic energy of photoelectrons emitted from a surface when photons of energy 6 eV fall on it is 4 eV. The stopping potential in volts is :

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Solution

The stopping potential (V) in a photoelectric effect experiment is related to the maximum kinetic energy (K.E) of the photoelectrons by the equation:

K.E = eV

where e is the charge of an electron (1.6 x 10^-19 C).

Given that the maximum kinetic energy of the photoelectrons is 4 eV, we can substitute this into the equation to find the stopping potential:

4 eV = eV

Therefore, the stopping potential V is 4 volts.

This problem has been solved

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