The maximum kinetic energy of photoelectrons emitted from a surface when photons of energy 6 eV fall on it is 4 eV. The stopping potential in volts is :
Question
The maximum kinetic energy of photoelectrons emitted from a surface when photons of energy 6 eV fall on it is 4 eV. The stopping potential in volts is :
Solution
The stopping potential (V) in a photoelectric effect experiment is related to the maximum kinetic energy (K.E) of the photoelectrons by the equation:
K.E = eV
where e is the charge of an electron (1.6 x 10^-19 C).
Given that the maximum kinetic energy of the photoelectrons is 4 eV, we can substitute this into the equation to find the stopping potential:
4 eV = eV
Therefore, the stopping potential V is 4 volts.
Similar Questions
When photons with a wavelength of 232 nm are incident on a metal with a work function =1.78 eV., the maximum kinetic energy (in eV to two decimal places) of photoelectrons emitted are
If maximum velocity with which an electron can be emitted from a photo cell is 4 × 108 cm/s, the stopping potential is (mass of electron = 9 × 10–31 kg)
The maximum kinetic energy of emitted photoelectrons, from different metalsurfaces, depends upon:A. Intensity of incident light only ⃝B. Frequency of the incident light only ⃝C. Nature of metal surface ⃝D. Both frequency of incident light and nature of metal surface
For the photoelectric effect, the maximum kinetic energy (Ek) of the photoelectrons is plotted against the frequency (v) of the incident photons as shown in figure. The slope of the graph gives
When light falls on a metal surface, the maximum kinetic energy of the emitted photo-electrons depends upon :-
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.