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A magnetic field of density (B) of 20μT is applied normally to a proton moving at a speed of 30,000 km/s causing it to rotate in a circular path as shown in the following diagram. Calculate the oscillation frequency.(proton charge = 1.6x10-19 C, proton mass = 1.67×10-27 kg)

Question

A magnetic field of density (B) of 20μT is applied normally to a proton moving at a speed of 30,000 km/s causing it to rotate in a circular path as shown in the following diagram. Calculate the oscillation frequency.(proton charge = 1.6x10-19 C, proton mass = 1.67×10-27 kg)

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Solution

The frequency of oscillation, also known as the cyclotron frequency, can be calculated using the formula:

f = qB/2πm

where: f is the frequency, q is the charge of the proton, B is the magnetic field density, and m is the mass of the proton.

Given: q = 1.6x10^-19 C, B = 20μT = 20x10^-6 T (since 1μT = 10^-6 T), and m = 1.67x10^-27 kg,

we can substitute these values into the formula:

f = (1.6x10^-19 C * 20x10^-6 T) / (2π * 1.67x10^-27 kg)

Solving this equation will give us the frequency of oscillation.

This problem has been solved

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