Calculate NMR frequency (in MHz) of the proton placed in a magnetic field of intensity1.4092T. Given: gn = 5.585; μn = 5.0510−27 JT−1
Question
Calculate NMR frequency (in MHz) of the proton placed in a magnetic field of intensity1.4092T. Given: gn = 5.585; μn = 5.0510−27 JT−1
Solution
To calculate the NMR frequency of a proton, we can use the formula:
ν = γB
where: ν is the NMR frequency, γ is the gyromagnetic ratio (which is equal to gn*μn/2π), B is the magnetic field intensity.
Given: gn = 5.585, μn = 5.05×10−27 JT−1, B = 1.4092 T,
we first calculate γ:
γ = gn*μn/2π = 5.585 * 5.05×10−27 JT−1 / 2π = 4.425×10^8 T^-1
Then we substitute γ and B into the formula to find ν:
ν = γB = 4.425×10^8 T^-1 * 1.4092 T = 623.6 MHz
So, the NMR frequency of the proton placed in a magnetic field of intensity 1.4092T is approximately 623.6 MHz.
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