The gradient of a line in the form y = mx + c is given by the coefficient of x, which is m. In this case, the equation of the line is given as y = 3kx - 11.

Here, the gradient of the line is given as 3. This means that 3k, the coefficient of x in the equation, is equal to 3.

To find the value of k, we can set up the equation 3k = 3 and solve for k.

Dividing both sides of the equation by 3, we get:

k = 3/3 = 1.

So, the value of k is 1.

Question

The gradient of a line in the form y = mx + c is given by the coefficient of x, which is m. In this case, the equation of the line is given as y = 3kx - 11.

Here, the gradient of the line is given as 3. This means that 3k, the coefficient of x in the equation, is equal to 3.

To find the value of k, we can set up the equation 3k = 3 and solve for k.

Dividing both sides of the equation by 3, we get:

k = 3/3 = 1.

So, the value of k is 1.

Knowee AI · Accepted Answer

The gradient of a line in the form y = mx + c is given by the coefficient of x, which is m. In this case, the equation of the line is given as y = 3kx - 11.

Here, the gradient of the line is given as 3. This means that 3k, the coefficient of x in the equation, is equal to 3.

To find the value of k, we can set up the equation 3k = 3 and solve for k.

Dividing both sides of the equation by 3, we get:

k = 3/3 = 1.

So, the value of k is 1.

Given that 3 is the gradient of the line with equation y = 3kx – 11, find the value of k.

Question

Solution

Similar Questions

Upgrade your grade with Knowee