To test the doctor's claim, we will use a one-sample t-test. Here are the steps:

Step 1: State the hypotheses. The first step is to state the null hypothesis and an alternative hypothesis.

Null hypothesis: The mean weight of babies is 6.1kg.
Alternative hypothesis: The mean weight of babies is not 6.1kg.

Step 2: Formulate an analysis plan. For this analysis, the significance level is defined as 0.05. Using sample data, we calculate the pooled sample standard deviation and the standard error. Using those measures, we compute the test statistic. Using the test statistic, we can find the P-value.

Step 3: Analyze sample data. Using sample data, we calculate the pooled sample standard deviation, the standard error, and the test statistic. Using the test statistic, we find the P-value.

Step 4: Interpret the results. If the P-value is less than the significance level, we reject the null hypothesis.

Let's calculate:

The mean (x̄) of the sample data is the sum of all the weights divided by the number of weights.

x̄ = (1.2 + 1.4 + 1.1 + 2.3 + 4.2 + 0.7 + 1.9 + 1.1 + 4.2 + 8.2) / 10 = 2.63 kg

The standard deviation (s) is calculated as follows:

s = sqrt{ [ (1.2-2.63)^2 + (1.4-2.63)^2 + (1.1-2.63)^2 + (2.3-2.63)^2 + (4.2-2.63)^2 + (0.7-2.63)^2 + (1.9-2.63)^2 + (1.1-2.63)^2 + (4.2-2.63)^2 + (8.2-2.63)^2 ] / (10-1) } = 2.19 kg

The standard error (SE) is calculated as follows:

SE = s / sqrt(n) = 2.19 / sqrt(10) = 0.69 kg

The t-score is calculated as follows:

t = (x̄ - μ) / SE = (2.63 - 6.1) / 0.69 = -5.03

Now, we need to find the P-value. The degrees of freedom is 10-1=9. Using the t-distribution table or a calculator, we find that the P-value is less than 0.0001.

Since the P-value is less than the significance level of 0.05, we reject the null hypothesis. Therefore, we have enough evidence to say that the mean weight of babies delivered at the hospital is not 6.1kg.

Question

To test the doctor's claim, we will use a one-sample t-test. Here are the steps:

Step 1: State the hypotheses. The first step is to state the null hypothesis and an alternative hypothesis.

Null hypothesis: The mean weight of babies is 6.1kg.
Alternative hypothesis: The mean weight of babies is not 6.1kg.

Step 2: Formulate an analysis plan. For this analysis, the significance level is defined as 0.05. Using sample data, we calculate the pooled sample standard deviation and the standard error. Using those measures, we compute the test statistic. Using the test statistic, we can find the P-value.

Step 3: Analyze sample data. Using sample data, we calculate the pooled sample standard deviation, the standard error, and the test statistic. Using the test statistic, we find the P-value.

Step 4: Interpret the results. If the P-value is less than the significance level, we reject the null hypothesis.

Let's calculate:

The mean (x̄) of the sample data is the sum of all the weights divided by the number of weights.

x̄ = (1.2 + 1.4 + 1.1 + 2.3 + 4.2 + 0.7 + 1.9 + 1.1 + 4.2 + 8.2) / 10 = 2.63 kg

The standard deviation (s) is calculated as follows:

s = sqrt{ [ (1.2-2.63)^2 + (1.4-2.63)^2 + (1.1-2.63)^2 + (2.3-2.63)^2 + (4.2-2.63)^2 + (0.7-2.63)^2 + (1.9-2.63)^2 + (1.1-2.63)^2 + (4.2-2.63)^2 + (8.2-2.63)^2 ] / (10-1) } = 2.19 kg

The standard error (SE) is calculated as follows:

SE = s / sqrt(n) = 2.19 / sqrt(10) = 0.69 kg

The t-score is calculated as follows:

t = (x̄ - μ) / SE = (2.63 - 6.1) / 0.69 = -5.03

Now, we need to find the P-value. The degrees of freedom is 10-1=9. Using the t-distribution table or a calculator, we find that the P-value is less than 0.0001.

Since the P-value is less than the significance level of 0.05, we reject the null hypothesis. Therefore, we have enough evidence to say that the mean weight of babies delivered at the hospital is not 6.1kg.

Knowee AI · Accepted Answer