Let X be a random variable with the following probability distribution.Value x of X P=Xx-20 0.05-10 0.100 0.2010 0.2020 0.1530 0.30Complete the following. (If necessary, consult a list of formulas.)(a) Find the expectation EX of X.=EX (b) Find the variance VarX of X.=VarX
Question
Let X be a random variable with the following probability distribution.Value x of X P=Xx-20 0.05-10 0.100 0.2010 0.2020 0.1530 0.30Complete the following. (If necessary, consult a list of formulas.)(a) Find the expectation EX of X.=EX (b) Find the variance VarX of X.=VarX
Solution
(a) The expectation or expected value (E[X]) of a random variable is calculated by multiplying each possible outcome by their respective probabilities and summing these products.
For the given probability distribution, the expectation E[X] is calculated as follows:
E[X] = (-20 * 0.05) + (-10 * 0.10) + (0 * 0.20) + (10 * 0.20) + (20 * 0.15) + (30 * 0.30) = -1 + -1 + 0 + 2 + 3 + 9 = 12
(b) The variance (Var[X]) of a random variable is calculated by subtracting the square of the expectation from the expectation of the squares.
First, calculate E[X^2] (the expectation of the squares):
E[X^2] = (-20^2 * 0.05) + (-10^2 * 0.10) + (0^2 * 0.20) + (10^2 * 0.20) + (20^2 * 0.15) + (30^2 * 0.30) = 200 + 100 + 0 + 200 + 600 + 2700 = 3800
Then, calculate Var[X] = E[X^2] - (E[X])^2:
Var[X] = 3800 - (12)^2 = 3800 - 144 = 3656
Similar Questions
Let X be a random variable with the following probability distribution.Value x of X P=Xx-10 0.050 0.0510 0.4520 0.45Complete the following. (If necessary, consult a list of formulas.)(a) Find the expectation EX of X.=EX (b) Find the variance VarX of X.=VarX
The discrete random variable X has the probability functionP (X = x) =kx if x = 2, 4, 6k(x − 2) if x = 80 otherwisewhere k is a constant.(a) Show that k = 118 .(b) Find the exact value of F (5).(c) Find the exact value of E(X).(d) Find the exact value of E(X2).(e) Calculate Var(3 − 4X).1
A random variable X has moment generating function m(t)=(5+exp(2t))/6. What is the variance of X?
Suppose X is a random variable with possible outcomes 0 and 2, with P( X = 2 ) = 0.3. The variance of X is
Find the standard deviation for the given probability distribution.xp(X)x.P(X)x2.P(X)00.21 10.08 20.08 30.36 40.27
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.