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a) If ๐‘ฅ = 2 + โˆš3, find the value of ๐‘ฅ + 1๐‘ฅ

Question

a) If ๐‘ฅ = 2 + โˆš3, find the value of ๐‘ฅ + 1๐‘ฅ

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Solution

Sure, here are the steps to solve the problem:

Step 1: Given ๐‘ฅ = 2 + โˆš3

Step 2: To find the value of ๐‘ฅ + 1/๐‘ฅ, we first need to find the value of 1/๐‘ฅ.

Step 3: To find 1/๐‘ฅ, we can use the formula for the reciprocal of a binomial a + b, which is 1/(a + b) = 1/a - b/a^2.

Step 4: Substituting a = 2 and b = โˆš3 into the formula, we get 1/๐‘ฅ = 1/2 - โˆš3/4.

Step 5: Now, we can find the value of ๐‘ฅ + 1/๐‘ฅ by adding ๐‘ฅ and 1/๐‘ฅ together.

Step 6: ๐‘ฅ + 1/๐‘ฅ = (2 + โˆš3) + (1/2 - โˆš3/4) = 2.5 + 0.25โˆš3.

So, the value of ๐‘ฅ + 1/๐‘ฅ is 2.5 + 0.25โˆš3.

This problem has been solved

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