An urn contains 6 red, 4 blue, 2 green and 3 yellow marbles. If two marbles are picked at random, what is the probability that both marbles are red ?Question 1Answera.1/7b.1/3c.2/15d.1/6
Question
An urn contains 6 red, 4 blue, 2 green and 3 yellow marbles. If two marbles are picked at random, what is the probability that both marbles are red ?Question 1Answera.1/7b.1/3c.2/15d.1/6
Solution
The total number of marbles in the urn is 6 (red) + 4 (blue) + 2 (green) + 3 (yellow) = 15 marbles.
The probability of picking a red marble on the first draw is 6 (red marbles) / 15 (total marbles) = 2/5.
After one red marble has been drawn, there are now 5 red marbles left and a total of 14 marbles in the urn.
So, the probability of picking a red marble on the second draw is 5 (red marbles) / 14 (total marbles).
The probability of both events happening (picking a red marble on the first draw and picking a red marble on the second draw) is the product of the probabilities of each event.
So, the probability that both marbles are red is (2/5) * (5/14) = 1/7.
So, the correct answer is a. 1/7.
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