Word CounterImplement Python program to find the number of words in a string Constraints:NAExample:Sample Input:Python Programming LanguageSample Output:3Explanation:The Number of words in the given string are 3Public Test Cases:# INPUT EXPECTED OUTPUT1 Python Programming Language3
Question
Word CounterImplement Python program to find the number of words in a string Constraints:NAExample:Sample Input:Python Programming LanguageSample Output:3Explanation:The Number of words in the given string are 3Public Test Cases:# INPUT EXPECTED OUTPUT1 Python Programming Language3
Solution
Sure, here is a simple Python program that counts the number of words in a string:
def word_counter(input_string):
# Split the string into words
words = input_string.split()
# Count the number of words
word_count = len(words)
return word_count
# Test the function
input_string = "Python Programming Language"
print(word_counter(input_string))
This program works by using the split() function to divide the input string into a list of words. The len() function is then used to count the number of items in this list, which is equal to the number of words in the original string.
Similar Questions
Write a program to count number of words in a given string whose length is greater than 3.For example:Input Resultpython is easier than C3
We are given a function countWordOccurrences that takes two string parameters sentence and word."Sentence" is a string made up of multiple words separated by spaces.We have to find how many times 'word' occurs in the given 'sentence'.The 'word' should be an exact match.Note: The case (uppercase/lowercase) of the letters in the word does NOT matter.InputFirst line contains space separated series of words which represents the string "sentence".Second line contains a single word "word".Constraints1 ≤ length(sentence), length(word) ≤ 104length(word) ≤ length(sentence)OutputWe have to return an integer which is the number of occurrences of the single word 'word' in the string 'sentence'.
In the first line of input, accept a sequence of space-separated words. In the second line of input, accept a single word. If this word is not present in the sequence, print NO. If this word is present in the sequence, then print YES and in the next line of the output, print the number of times the word appears in the sequence.words = input().split('')test = input()if test not in words: Print('No')else: Print('YES') count = 0 for word in words: if test == word: count -= 1 Print(count)Sample Test CasesDownload All Test Case 1InputExpected OutputActual Outputa good collection of wordstheNOTest Case 2InputExpected OutputActual Outputno sentence can begin with because because because is a conjunctionbecauseYES3
Select the correct implementation of a piece of code that accepts a sentence as input and prints the number of words in it. A sentence is just a sequence of words with a space between consecutive words. You can assume that the sentence will not have any other punctuation marks. You can also assume that the input string will have at least one word.1sentence = input()2space = ' ' # there is a single space between the quotes3num_words = sentence.count(space)4print(num_words)1sentence = input()2space = ' ' # there is a single space between the quotes3num_words = sentence.count(space) + 14print(num_words)1sentence = int(input())2space = ' ' # there is a single space between the quotes3num_words = sentence.count(space)4print(num_words)1sentence = input()2num_words = len(sentence)3print(num_words)
Palindrome CountWrite a python program to count the number of palindrome strings that occurred in the given string. Input:The input consists of a string.Output:count number of palindrome stringsConstraints:1 < str < 10000Example:Input:madamOutput:2
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