Select the correct implementation of a piece of code that accepts a sentence as input and prints the number of words in it. A sentence is just a sequence of words with a space between consecutive words. You can assume that the sentence will not have any other punctuation marks. You can also assume that the input string will have at least one word.1sentence = input()2space = ' ' # there is a single space between the quotes3num_words = sentence.count(space)4print(num_words)1sentence = input()2space = ' ' # there is a single space between the quotes3num_words = sentence.count(space) + 14print(num_words)1sentence = int(input())2space = ' ' # there is a single space between the quotes3num_words = sentence.count(space)4print(num_words)1sentence = input()2num_words = len(sentence)3print(num_words)

Raghu's tutor provides him a simple sentence and asks him to count the number of words in the sentence. The words are separated by space.Example, if the tutor provides the sentence as "Welcome to Java", the output should beNumber of words 3The words are WelcometoJavaFill the space in the below code so that the code fulfills his requirement. Code :                Scanner sc=new Scanner(System.in); String str=sc.nextLine(); String words[ ]  =   ; int count=  ;  //count holds the number of words in the sentence System.out.println("Number of words "+); System.out.println("The words are "); for(String    :     ) //for each loop System.out.println(x);

In the first line of input, accept a sequence of space-separated words. In the second line of input, accept a single word. If this word is not present in the sequence, print NO. If this word is present in the sequence, then print YES and in the next line of the output, print the number of times the word appears in the sequence.words = input().split('')test = input()if test not in words:    Print('No')else:    Print('YES')    count = 0    for word in words:        if test == word:            count -= 1                    Print(count)Sample Test CasesDownload All Test Case 1InputExpected OutputActual Outputa good collection of wordstheNOTest Case 2InputExpected OutputActual Outputno sentence can begin with because because because is a conjunctionbecauseYES3

We are given a function countWordOccurrences that takes two string parameters sentence and word."Sentence" is a string made up of multiple words separated by spaces.We have to find how many times 'word' occurs in the given 'sentence'.The 'word' should be an exact match.Note: The case (uppercase/lowercase) of the letters in the word does NOT matter.InputFirst line contains space separated series of words which represents the string "sentence".Second line contains a single word "word".Constraints1 ≤ length(sentence), length(word) ≤ 104length(word) ≤ length(sentence)OutputWe have to return an integer which is the number of occurrences of the single word 'word' in the string 'sentence'.

Write a C program to read a sentence through keyboard and to display the count ofwhite spaces in the given sentence.

Problem StatementWrite a program to count the lines, words and characters in a given text.Input FormatInput the text (Ctrl+D on a new line to end input)Output FormatPrint the no of lines, words, charactersSample Input 1This is a sample text.It has multiple lines.Each line contains words.Sample Output 1Lines: 3Words: 12Characters: 80Sample Input 2Hello WorldHappy CodingSample OutputLines: 2Words: 4Characters: 23