During a snowball fight, two balls with masses of 0.4 and 0.6 kg, respectively, are thrown in such a manner that they meet head-on and combine to form a single mass. The magnitude of initial velocity for each is 20 m/s. What is the speed of the 1.0-kg mass immediately after collision?Select one:a.3 m/sb.4 m/sc.zerod.5 m/s
Question
During a snowball fight, two balls with masses of 0.4 and 0.6 kg, respectively, are thrown in such a manner that they meet head-on and combine to form a single mass. The magnitude of initial velocity for each is 20 m/s. What is the speed of the 1.0-kg mass immediately after collision?Select one:a.3 m/sb.4 m/sc.zerod.5 m/s
Solution 1
This problem can be solved using the principle of conservation of momentum. The total momentum before the collision is equal to the total momentum after the collision.
Before the collision, the momentum of each snowball is its mass times its velocity. The total momentum is the sum of the momentum of each snowball.
The momentum of the 0.4 kg snowball is (0.4 kg)(20 m/s) = 8 kgm/s. The momentum of the 0.6 kg snowball is (0.6 kg)(20 m/s) = 12 kgm/s. So, the total initial momentum is 8 kgm/s + 12 kgm/s = 20 kg*m/s.
After the collision, the two snowballs stick together and form a single mass of 1.0 kg. We can set the final momentum of this combined mass equal to the total initial momentum and solve for the final velocity (v).
(1.0 kg)(v) = 20 kg*m/s So, v = 20 m/s.
Therefore, the speed of the 1.0-kg mass immediately after the collision is 20 m/s. However, this option is not available in the choices given. It seems there might be a mistake in the problem or the answer choices.
Solution 2
This problem can be solved using the principle of conservation of momentum. The total momentum before the collision is equal to the total momentum after the collision.
Step 1: Calculate the initial momentum of each snowball. The momentum (p) of an object is given by the product of its mass (m) and velocity (v), i.e., p = mv.
For the 0.4 kg snowball: p1_initial = m1 * v1 = 0.4 kg * 20 m/s = 8 kgm/s For the 0.6 kg snowball: p2_initial = m2 * v2 = 0.6 kg * 20 m/s = 12 kgm/s
Step 2: Calculate the total initial momentum. The total initial momentum (p_initial) is the sum of the initial momenta of the two snowballs, i.e., p_initial = p1_initial + p2_initial = 8 kgm/s + 12 kgm/s = 20 kg*m/s
Step 3: Calculate the final momentum. After the collision, the two snowballs combine to form a single mass. The final momentum (p_final) is therefore given by the product of the combined mass (m_final) and the final velocity (v_final), i.e., p_final = m_final * v_final.
Step 4: Set the total initial momentum equal to the total final momentum and solve for the final velocity. According to the principle of conservation of momentum, p_initial = p_final. Therefore, 20 kg*m/s = 1.0 kg * v_final. Solving for v_final gives v_final = 20 m/s / 1.0 kg = 20 m/s.
Therefore, the speed of the 1.0-kg mass immediately after the collision is 20 m/s. However, this option is not available in the given choices. Please check the problem statement or the given choices again.
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