Knowee
Questions
Features
Study Tools

Two objects of the same mass move along the same line in opposite directions. The first mass is moving with speed v. The objects collide in a perfectly inelastic collision and move with speed 0.100v in the direction of the velocity of the first mass before the collision. What was the speed of the second mass before the collision?Group of answer choices0.900v0.800vnone of these0.00v1.200v10.0v

Question

Two objects of the same mass move along the same line in opposite directions. The first mass is moving with speed v. The objects collide in a perfectly inelastic collision and move with speed 0.100v in the direction of the velocity of the first mass before the collision. What was the speed of the second mass before the collision?Group of answer choices0.900v0.800vnone of these0.00v1.200v10.0v

🧐 Not the exact question you are looking for?Go ask a question

Solution

Let's solve this problem step by step:

  1. Let's assume the mass of both objects is "m".
  2. The first mass is moving with speed "v" in one direction.
  3. The second mass is moving in the opposite direction.
  4. After the collision, the objects stick together and move with a speed of 0.100v in the direction of the first mass's velocity before the collision.
  5. Let's denote the speed of the second mass before the collision as "v2".

Now, let's apply the principle of conservation of momentum:

Before the collision: Momentum of the first mass = mass of the first mass * velocity of the first mass = m * v Momentum of the second mass = mass of the second mass * velocity of the second mass = m * v2

After the collision: Momentum of the combined masses = (mass of the first mass + mass of the second mass) * velocity of the combined masses = 2m * 0.100v

According to the principle of conservation of momentum, the momentum before the collision should be equal to the momentum after the collision:

m * v + m * v2 = 2m * 0.100v

Simplifying the equation:

v + v2 = 0.200v

Now, let's solve for v2:

v2 = 0.200v - v v2 = 0.200v - 1v v2 = -0.800v

Since the speed cannot be negative, the speed of the second mass before the collision is 0.800v.

Therefore, the correct answer is 0.800v.

This problem has been solved

Similar Questions

A body of mass 4 kg moving at a speed of 3 m/s collides with another body of mass 2 kg moving at 2 m/s in the opposite direction. If the collision is perfectly inelastic, find the velocity of the two bodies after the collision.*1 point1.33 m/s2.34 m/s3.22 m/s4.00 m/s

During a snowball fight, two balls with masses of 0.4 and 0.6 kg, respectively, are thrown in such a manner that they meet head-on and combine to form a single mass. The magnitude of initial velocity for each is 20 m/s. What is the speed of the 1.0-kg mass immediately after collision?Select one:a.3 m/sb.4 m/sc.zerod.5 m/s

An object of mass 2m moving at velocity 3v collides with a stationary object of mass 4m. The objects stick together after the collision. What is the finalspeed and the change in total kinetic energy immediately after the collision?Final speedChange in total kinetic energyA.V3 mv^2B.V6 mv^2C.2v3mv^2D.2v6 mv^2

A .5 kg mass moving to the right at 1 m/s collides with a 1.5 kg mass moving to the left at .5 m/s. After the collision, the .5 kg mass moves to the left at 1.25 m/s. What is the velocity of the 1.5 kg mass after the collision?1 m/s.5 m/s.25 m/s0 m/s

Consider a collision between two marbles . A 100 g marble moving right at 5.4 m/s strikes a 14 g marble at rest. After the collision, if the 14 g marble moves forward with speed 1.2 m/s, what is the speed, in m/s, of 100 g marble immediately after the collision?

1/3

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.