The diagrams show two different circuits.R R RThe cells in each circuit have the same electromotive force (e.m.f.) and negligible internalresistance. The three resistors each have the same resistance R.In the circuit on the left, the power dissipated in the resistor is P.What is the total power dissipated in the circuit on the right?A 4P B 2P C P D 2P
Question
The diagrams show two different circuits.R R RThe cells in each circuit have the same electromotive force (e.m.f.) and negligible internalresistance. The three resistors each have the same resistance R.In the circuit on the left, the power dissipated in the resistor is P.What is the total power dissipated in the circuit on the right?A 4P B 2P C P D 2P
Solution
The question seems to be incomplete as the diagrams of the circuits are not provided. However, I can provide a general explanation.
In the first circuit, the power dissipated in the resistor is P. This power is given by the formula P = V^2/R, where V is the voltage across the resistor and R is the resistance.
In the second circuit, if the resistors are arranged in series, the total resistance would be 3R and the power dissipated would be V^2/(3R) which is P/3. If the resistors are arranged in parallel, the total resistance would be R/3 and the power dissipated would be 3V^2/R which is 3P.
So, without the diagrams, it's impossible to give a definite answer. The total power dissipated in the circuit on the right could be P/3 or 3P depending on the arrangement of the resistors.
Similar Questions
The total power dissipated in a parallel circuit is equal to thepower in the largest resistorpower in the smallest resistoraverage of the power in all resistorssum of the power in all resistors
35 The diagram shows a cell of electromotive force (e.m.f.) 3.0 V and internal resistance 4.7 connected across a lamp. The lamp has a resistance of 9.3 .4.7 9.3 3.0 VWhat is the power dissipated by the internal resistance of the cell?A 0.22 W B 0.43 W C 0.64 W D 1.0 W36 A circuit consists of a battery, a high-resistance voltmeter and four fixed resistors, as shown. Thebattery has an electromotive force (e.m.f.) of 15.0 V and negligible internal resistance.V24.0 6.0 6.0 9.0 15.0 VWhat is the reading on the voltmeter?A 3.0 V B 6.0 V C 9.0 V D 12.0 V
In the given figure, the emf of the cell is 2.2 V and if internal resistance is 0.6Ω. Calculate the power dissipated in the whole circuit :
Two resistors R1 and R2 of 4Ω and 6Ω are connected in parallel across a battery. The ratio of power dissipated in them, P1: P2 will be.
The total power dissipated in a series circuit is equal to thepower in the largest resistorpower in the smallest resistoraverage of the power in all resistorssum of the power in all resistors
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.