In the given figure, the emf of the cell is 2.2 V and if internal resistance is 0.6Ω. Calculate the power dissipated in the whole circuit :
Question
In the given figure, the emf of the cell is 2.2 V and if internal resistance is 0.6Ω. Calculate the power dissipated in the whole circuit :
Solution
To calculate the power dissipated in the whole circuit, we first need to find the total current flowing in the circuit.
Step 1: Calculate the total current (I) in the circuit.
The total current in the circuit can be calculated using Ohm's law, which states that the current is equal to the voltage (V) divided by the resistance (R). In this case, the total voltage is the emf of the cell (2.2 V) and the total resistance is the internal resistance (0.6 Ω).
So, I = V/R = 2.2 V / 0.6 Ω = 3.67 A
Step 2: Calculate the power (P) dissipated in the circuit.
The power dissipated in a circuit can be calculated using the formula P = I^2 * R, where I is the current and R is the resistance.
So, P = (3.67 A)^2 * 0.6 Ω = 8.08 W
Therefore, the power dissipated in the whole circuit is 8.08 W.
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