The average weight of A, B and C is “45 mg”. If the average weight of A and B be “40 mg” and that of B and C be “43 mg”, then the weight of B is:17 mg20 mg26 mg31 mg
Question
The average weight of A, B and C is “45 mg”. If the average weight of A and B be “40 mg” and that of B and C be “43 mg”, then the weight of B is:17 mg20 mg26 mg31 mg
Solution
Let's solve this step by step:
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The average weight of A, B, and C is 45 mg. This means the total weight of A, B, and C is 45 mg * 3 = 135 mg.
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The average weight of A and B is 40 mg. This means the total weight of A and B is 40 mg * 2 = 80 mg.
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The average weight of B and C is 43 mg. This means the total weight of B and C is 43 mg * 2 = 86 mg.
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If we add the total weights of A and B and B and C, we get 80 mg + 86 mg = 166 mg. This is more than the total weight of A, B, and C, which is 135 mg. The difference is the weight of B, because B has been counted twice.
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So, the weight of B is 166 mg - 135 mg = 31 mg.
So, the correct answer is 31 mg.
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