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The average weight of A, B, C is 50 kgs weight of B is 20 kgs less than A’s weight and 5 kgs more than C’s weight. what will be the average weight of A, B, C and D. If D weights 2 kgs more than C?

Question

The average weight of A, B, C is 50 kgs weight of B is 20 kgs less than A’s weight and 5 kgs more than C’s weight. what will be the average weight of A, B, C and D. If D weights 2 kgs more than C?

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Solution

Sure, let's solve this step by step:

  1. The average weight of A, B, C is 50 kgs. This means the total weight of A, B, C is 50 * 3 = 150 kgs.

  2. B's weight is 20 kgs less than A's weight and 5 kgs more than C's weight. Let's denote A's weight as a, B's weight as b, and C's weight as c. So we have: a = b + 20 c = b - 5

  3. Substitute a and c into the total weight equation, we get: b + 20 + b + b - 5 = 150 3b + 15 = 150 3b = 135 b = 45 kgs

  4. Substitute b = 45 into a = b + 20 and c = b - 5, we get: a = 65 kgs c = 40 kgs

  5. D's weight is 2 kgs more than C's weight, so D's weight is 40 + 2 = 42 kgs.

  6. The average weight of A, B, C, D is (65 + 45 + 40 + 42) / 4 = 48 kgs.

This problem has been solved

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