Using the following equation, find the center and radius:x2 + 2x + y2 + 4y = 20Group of answer choicesThe center is located at (1, 2), and the radius is 25.The center is located at (−1, 2), and the radius is 25.The center is located at (−1, −2), and the radius is 5.The center is located at (1, 2), and the radius is 5.

The equation given is in the form of a circle equation, but it's not in the standard form. The standard form of a circle equation is (x-h)² + (y-k)² = r², where (h,k) is the center of the circle and r is the radius.

First, we need to rewrite the given equation in the standard form. We can do this by completing the square for the x terms and the y terms separately.

The given equation is x² + 2x + y² + 4y = 20.

Rearrange the equation to group the x terms and y terms together:

(x² + 2x) + (y² + 4y) = 20.

To complete the square, we take half of the coefficient of x, square it and add it to both sides. Half of 2 is 1, and 1 squared is 1. Do the same for the y terms. Half of 4 is 2, and 2 squared is 4.

(x² + 2x + 1) + (y² + 4y + 4) = 20 + 1 + 4.

Simplify the equation:

(x + 1)² + (y + 2)² = 25.

Now the equation is in the standard form of a circle equation. The center of the circle is at the point (h,k) = (-1,-2) and the radius of the circle is the square root of 25, which is 5.

So, the center is located at (-1, -2), and the radius is 5.