Q 2: A student is carrying out an experiment to determine the time period of mass-attached to aspring using the setup as shown in the figure 2. Figure 2 He adjusted the position of pointer at 0.0 cm when there is no load suspended with the spring. When a 100 g mass is suspended with the spring, then the new position is shown in the figure. (i) What is the value of force that 100 g of mass exerts on the spring? [1 ] 7 Force = N (ii) What is the extension in the spring? [1] Extension = cm (iii) What is the value of spring constant k? [1 ] k = (iv) What is the time period of mass-attached to the spring if the mass is pushed downward and left to oscillate? [1.5 ] T = (v) Using the result of part (iv), find frequency of the oscillations. [1.5 ] f =

(i) To determine the force exerted by a 100 g mass on the spring, we need to convert the mass to kilograms. Since 1 kg is equal to 1000 g, the mass of 100 g is equal to 0.1 kg. The force exerted by the mass can be calculated using the formula F = mg, where F is the force, m is the mass, and g is the acceleration due to gravity. Assuming the acceleration due to gravity is 9.8 m/s^2, we can calculate the force as follows:

F = (0.1 kg) * (9.8 m/s^2) = 0.98 N

Therefore, the value of force that the 100 g mass exerts on the spring is 0.98 N.

(ii) To find the extension in the spring, we need to measure the difference in position between the unloaded spring and the spring with the 100 g mass attached. From the figure, we can see that the difference in position is 7 cm. Therefore, the extension in the spring is 7 cm.

(iii) The spring constant, denoted by k, can be calculated using Hooke's Law, which states that the force exerted by a spring is directly proportional to its extension. The formula for Hooke's Law is F = kx, where F is the force, k is the spring constant, and x is the extension. Rearranging the formula, we have k = F/x. Substituting the values we have, we get:

k = (0.98 N) / (7 cm) = 0.14 N/cm

Therefore, the value of the spring constant k is 0.14 N/cm.

(iv) The time period of the mass attached to the spring can be calculated using the formula T = 2π√(m/k), where T is the time period, m is the mass, and k is the spring constant. Substituting the values we have, we get:

T = 2π√(0.1 kg / 0.14 N/cm)

Calculating this value will give us the time period of the oscillations.

(v) Once we have the time period T, we can calculate the frequency of the oscillations using the formula f = 1/T. Substituting the value of T we obtained in part (iv), we can calculate the frequency f.