To solve this problem, we need to use Hooke's Law, which states that the force (F) exerted by a spring is directly proportional to the extension (x) it causes. This can be written as F = kx, where k is the spring constant.

Step 1: Calculate the spring constant (k) using the given weight and extension.
The weight of 2.0 N causes an extension of 6.0 cm. We can convert this to meters by dividing by 100, so the extension is 0.06 m.

So,
2.0 N = k * 0.06 m
Solving for k, we get k = 2.0 N / 0.06 m = 33.33 N/m.

Step 2: Calculate the new extension (x) when an 8.0 N weight is hung from the spring.
We can rearrange Hooke's Law to solve for x: x = F / k.

So,
x = 8.0 N / 33.33 N/m = 0.24 m.

Therefore, the new extension of the spring when an 8.0 N weight is hung from it is 0.24 m, or 24 cm.

Question

To solve this problem, we need to use Hooke's Law, which states that the force (F) exerted by a spring is directly proportional to the extension (x) it causes. This can be written as F = kx, where k is the spring constant.

Step 1: Calculate the spring constant (k) using the given weight and extension.
The weight of 2.0 N causes an extension of 6.0 cm. We can convert this to meters by dividing by 100, so the extension is 0.06 m.

So, 
2.0 N = k * 0.06 m
Solving for k, we get k = 2.0 N / 0.06 m = 33.33 N/m.

Step 2: Calculate the new extension (x) when an 8.0 N weight is hung from the spring.
We can rearrange Hooke's Law to solve for x: x = F / k.

So, 
x = 8.0 N / 33.33 N/m = 0.24 m.

Therefore, the new extension of the spring when an 8.0 N weight is hung from it is 0.24 m, or 24 cm.

Knowee AI · Accepted Answer

To solve this problem, we need to use Hooke's Law, which states that the force (F) exerted by a spring is directly proportional to the extension (x) it causes. This can be written as F = kx, where k is the spring constant.

Step 1: Calculate the spring constant (k) using the given weight and extension.
The weight of 2.0 N causes an extension of 6.0 cm. We can convert this to meters by dividing by 100, so the extension is 0.06 m.

So, 
2.0 N = k * 0.06 m
Solving for k, we get k = 2.0 N / 0.06 m = 33.33 N/m.

Step 2: Calculate the new extension (x) when an 8.0 N weight is hung from the spring.
We can rearrange Hooke's Law to solve for x: x = F / k.

So, 
x = 8.0 N / 33.33 N/m = 0.24 m.

Therefore, the new extension of the spring when an 8.0 N weight is hung from it is 0.24 m, or 24 cm.

A weight of 2.0 N is hung from a spring. The extension produced is 6.0 cm. The 2.0 N weight is removed and an 8.0 N weight is hung from the spring. The spring does not pass its limit of proportionality.What is the new extension of the spring?

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