Suppose ๐ = ๐(๐ข, ๐ฃ, ๐ค), ๐ = ๐(๐ข, ๐ฃ, ๐ค), ๐ = ๐(๐ข. ๐ฃ. ๐ค), and ๐ข = ๐ข(๐, ๐ , ๐ก), ๐ฃ =๐ฃ(๐, ๐ , ๐ก), ๐ค = ๐ค(๐, ๐ , ๐ก). Then, write the formula for the Jacobian ๐(๐,๐,๐)๐(๐,๐ ,๐ก)
Question
Suppose ๐ = ๐(๐ข, ๐ฃ, ๐ค), ๐ = ๐(๐ข, ๐ฃ, ๐ค), ๐ = ๐(๐ข. ๐ฃ. ๐ค), and ๐ข = ๐ข(๐, ๐ , ๐ก), ๐ฃ =๐ฃ(๐, ๐ , ๐ก), ๐ค = ๐ค(๐, ๐ , ๐ก). Then, write the formula for the Jacobian ๐(๐,๐,๐)๐(๐,๐ ,๐ก)
Solution 1
Given ๐ = ๐(๐ข, ๐ฃ, ๐ค), ๐ = ๐(๐ข, ๐ฃ, ๐ค), ๐ = ๐(๐ข. ๐ฃ. ๐ค), and ๐ข = ๐ข(๐, ๐ , ๐ก), ๐ฃ =๐ฃ(๐, ๐ , ๐ก), ๐ค = ๐ค(๐, ๐ , ๐ก), the formula for the Jacobian ๐(๐,๐,๐)๐(๐,๐ ,๐ก) is as follows:
๐(๐,๐,๐)๐(๐,๐ ,๐ก) = ๐(๐,๐,๐)๐(๐ข,๐ฃ,๐ค) * ๐(๐ข,๐ฃ,๐ค)๐(๐,๐ ,๐ก)
This can be further expanded as:
๐(๐,๐,๐)๐(๐,๐ ,๐ก) = ๐๐๐๐ข * ๐๐ข๐๐ + ๐๐๐๐ฃ * ๐๐ฃ๐๐ + ๐๐๐๐ค * ๐๐ค๐๐ + ๐๐๐๐ข * ๐๐ข๐๐ + ๐๐๐๐ฃ * ๐๐ฃ๐๐ + ๐๐๐๐ค * ๐๐ค๐๐ + ๐๐๐๐ข * ๐๐ข๐๐ก + ๐๐๐๐ฃ * ๐๐ฃ๐๐ก + ๐๐๐๐ค * ๐๐ค๐๐ก
This formula represents the partial derivatives of ๐, ๐, and ๐ with respect to ๐, ๐ , and ๐ก, respectively.
Solution 2
Given ๐ = ๐(๐ข, ๐ฃ, ๐ค), ๐ = ๐(๐ข, ๐ฃ, ๐ค), ๐ = ๐(๐ข. ๐ฃ. ๐ค), and ๐ข = ๐ข(๐, ๐ , ๐ก), ๐ฃ =๐ฃ(๐, ๐ , ๐ก), ๐ค = ๐ค(๐, ๐ , ๐ก), the formula for the Jacobian ๐(๐,๐,๐)๐(๐,๐ ,๐ก) is as follows:
๐(๐,๐,๐)๐(๐,๐ ,๐ก) = ๐(๐,๐,๐)๐(๐ข,๐ฃ,๐ค) * ๐(๐ข,๐ฃ,๐ค)๐(๐,๐ ,๐ก)
This can be further expanded as:
๐(๐,๐,๐)๐(๐,๐ ,๐ก) = ๐๐๐๐ข * ๐๐ข๐๐ + ๐๐๐๐ฃ * ๐๐ฃ๐๐ + ๐๐๐๐ค * ๐๐ค๐๐ + ๐๐๐๐ข * ๐๐ข๐๐ + ๐๐๐๐ฃ * ๐๐ฃ๐๐ + ๐๐๐๐ค * ๐๐ค๐๐ + ๐๐๐๐ข * ๐๐ข๐๐ก + ๐๐๐๐ฃ * ๐๐ฃ๐๐ก + ๐๐๐๐ค * ๐๐ค๐๐ก
where ๐๐๐๐ข, ๐๐๐๐ฃ, ๐๐๐๐ค, ๐๐๐๐ข, ๐๐๐๐ฃ, ๐๐๐๐ค, ๐๐๐๐ข, ๐๐๐๐ฃ, ๐๐๐๐ค represent the partial derivatives of ๐, ๐, ๐ with respect to ๐ข, ๐ฃ, ๐ค respectively, and ๐๐ข๐๐, ๐๐ข๐๐ , ๐๐ข๐๐ก, ๐๐ฃ๐๐, ๐๐ฃ๐๐ , ๐๐ฃ๐๐ก, ๐๐ค๐๐, ๐๐ค๐๐ , ๐๐ค๐๐ก represent the partial derivatives of ๐ข, ๐ฃ, ๐ค with respect to ๐, ๐ , ๐ก respectively.
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