Given that๐(๐ฅ)=2๐ฅโ3 and ๐(๐ฅ)=1โ๐ฅ4solve (๐โ๐โ1)(๐ฅ)=(๐โ๐)(๐ฅ).
Question
Given that๐(๐ฅ)=2๐ฅโ3 and ๐(๐ฅ)=1โ๐ฅ4solve (๐โ๐โ1)(๐ฅ)=(๐โ๐)(๐ฅ).
Solution
To solve the equation (๐โ๐โ1)(๐ฅ)=(๐โ๐)(๐ฅ), we first need to understand what the notation means.
The notation (๐โ๐)(๐ฅ) means f(g(x)), i.e., the function f is applied to the result of function g(x). Similarly, (๐โ๐โ1)(๐ฅ) means f(g^(-1)(x)), i.e., the function f is applied to the inverse of function g(x).
Given ๐(๐ฅ)=2๐ฅโ3 and ๐(๐ฅ)=1โ๐ฅ^4, we can write:
(๐โ๐)(๐ฅ) = f(g(x)) = 2(1-x^4) - 3 = 2 - 2x^4 - 3 = -2x^4 - 1.
To find (๐โ๐โ1)(๐ฅ), we first need to find the inverse of g(x), g^(-1)(x).
The function ๐(๐ฅ)=1โ๐ฅ^4 can be rewritten as x = sqrt[4]{1 - g}, so g^(-1)(x) = sqrt[4]{1 - x}.
Then, (๐โ๐โ1)(๐ฅ) = f(g^(-1)(x)) = 2sqrt[4]{1 - x} - 3.
Setting (๐โ๐โ1)(๐ฅ) = (๐โ๐)(๐ฅ), we get:
-2x^4 - 1 = 2sqrt[4]{1 - x} - 3.
Solving this equation will give us the value(s) of x that satisfy the equation. However, this is a complex equation that may not have a simple algebraic solution. It may require numerical methods to solve.
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