This is a problem of inverse variation, where the time (t) it takes to travel between two cities varies inversely with the speed (s) of the car. This relationship can be expressed as t = k/s, where k is the constant of variation.

Step 1: Find the constant of variation (k)
We know that the trip takes 12 hours for a car moving at 63 mph. We can substitute these values into the equation to find k:
12 = k/63
Solving for k gives k = 12 * 63 = 756

Step 2: Find the time it takes for a car moving at 28 mph
Now that we know k, we can find the time it takes for a car moving at 28 mph by substitifying these values into the equation:
t = 756/28
Solving for t gives t = 27 hours

So, the trip would take 27 hours for a car moving at 28 mph.

Question

This is a problem of inverse variation, where the time (t) it takes to travel between two cities varies inversely with the speed (s) of the car. This relationship can be expressed as t = k/s, where k is the constant of variation.

Step 1: Find the constant of variation (k)
We know that the trip takes 12 hours for a car moving at 63 mph. We can substitute these values into the equation to find k:
12 = k/63
Solving for k gives k = 12 * 63 = 756

Step 2: Find the time it takes for a car moving at 28 mph
Now that we know k, we can find the time it takes for a car moving at 28 mph by substitifying these values into the equation:
t = 756/28
Solving for t gives t = 27 hours

So, the trip would take 27 hours for a car moving at 28 mph.

Knowee AI · Accepted Answer

This is a problem of inverse variation, where the time (t) it takes to travel between two cities varies inversely with the speed (s) of the car. This relationship can be expressed as t = k/s, where k is the constant of variation.

Step 1: Find the constant of variation (k)
We know that the trip takes 12 hours for a car moving at 63 mph. We can substitute these values into the equation to find k:
12 = k/63
Solving for k gives k = 12 * 63 = 756

Step 2: Find the time it takes for a car moving at 28 mph
Now that we know k, we can find the time it takes for a car moving at 28 mph by substitifying these values into the equation:
t = 756/28
Solving for t gives t = 27 hours

So, the trip would take 27 hours for a car moving at 28 mph.

The time it takes to cover the distance between two cities by car varies inversely with the speed of the car. The trip takes 12 hours for a car moving at 63 mph. How long does the trip take for a car moving at 28 mph ?hours

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