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On a car trip, the time of trip varies inversely with the speed traveled. One car drove 81 mph and it took them 32 minutes. If a different car made the same trip at a speed of 48 mph, how many minutes would the trip take?

Question

On a car trip, the time of trip varies inversely with the speed traveled. One car drove 81 mph and it took them 32 minutes. If a different car made the same trip at a speed of 48 mph, how many minutes would the trip take?

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Solution

Sure, let's solve this problem step by step.

  1. First, we need to understand the relationship between the time of the trip and the speed traveled. In this case, the time of the trip varies inversely with the speed traveled. This means that as the speed increases, the time decreases and vice versa. This can be represented by the equation T = k/S, where T is the time, S is the speed, and k is a constant.

  2. We know that one car drove at 81 mph and it took them 32 minutes. We can use this information to find the value of k. Substituting these values into the equation gives us 32 = k/81. Solving for k gives us k = 32 * 81 = 2592.

  3. Now we know the value of k, we can find out how long it would take a different car to make the same trip at a speed of 48 mph. Substituting these values into the equation gives us T = 2592/48.

  4. Solving for T gives us T = 54 minutes. So, the trip would take 54 minutes if the car traveled at a speed of 48 mph.

This problem has been solved

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