To solve this problem, we need to use the formula for the diffraction angle in a medium with a moving grating, which is given by:

sin(θ) = λf/v

where:
- λ is the wavelength of the light,
- f is the frequency of the ultrasonic wave,
- v is the velocity of the ultrasonic wave,
- θ is the diffraction angle.

First, we need to convert the wavelength from Angstroms (Å) to meters (m) since the velocity is given in m/s. 1 Å = 1e-10 m, so λ = 5893 Å = 5893e-10 m = 5.893e-7 m.

Next, we substitute the given values into the formula:

sin(θ) = (5.893e-7 m)(25e3 Hz) / 800 m/s
= 0.01835

Finally, we find the angle θ by taking the inverse sine (sin^-1) of the result:

θ = sin^-1(0.01835) = 1.05 degrees

So, the first order angle of diffraction is approximately 1.05 degrees.

Question

To solve this problem, we need to use the formula for the diffraction angle in a medium with a moving grating, which is given by:

sin(θ) = λf/v

where:
- λ is the wavelength of the light,
- f is the frequency of the ultrasonic wave,
- v is the velocity of the ultrasonic wave,
- θ is the diffraction angle.

First, we need to convert the wavelength from Angstroms (Å) to meters (m) since the velocity is given in m/s. 1 Å = 1e-10 m, so λ = 5893 Å = 5893e-10 m = 5.893e-7 m.

Next, we substitute the given values into the formula:

sin(θ) = (5.893e-7 m)(25e3 Hz) / 800 m/s
       = 0.01835

Finally, we find the angle θ by taking the inverse sine (sin^-1) of the result:

θ = sin^-1(0.01835) = 1.05 degrees

So, the first order angle of diffraction is approximately 1.05 degrees.

Knowee AI · Accepted Answer

To solve this problem, we need to use the formula for the diffraction angle in a medium with a moving grating, which is given by:

sin(θ) = λf/v

where:
- λ is the wavelength of the light,
- f is the frequency of the ultrasonic wave,
- v is the velocity of the ultrasonic wave,
- θ is the diffraction angle.

First, we need to convert the wavelength from Angstroms (Å) to meters (m) since the velocity is given in m/s. 1 Å = 1e-10 m, so λ = 5893 Å = 5893e-10 m = 5.893e-7 m.

Next, we substitute the given values into the formula:

sin(θ) = (5.893e-7 m)(25e3 Hz) / 800 m/s
       = 0.01835

Finally, we find the angle θ by taking the inverse sine (sin^-1) of the result:

θ = sin^-1(0.01835) = 1.05 degrees

So, the first order angle of diffraction is approximately 1.05 degrees.

A light of wavelength 5893 Å is passed through a liquid throughwhich an ultrasonic wave of 25kHz is propagating. What will bethe angle of first order angle of diffraction if velocity of wave is800 m/s?

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