To calculate the velocity of ultrasonic waves in the liquid, we can use the Bragg's law of diffraction, which states that nλ = 2d sin θ, where:

- n is the order of diffraction, which is 1 in this case.
- λ is the wavelength of the light, which is 6000 Å or 6000*10^-10 m.
- d is the spacing between the layers in the crystal, which is what we're trying to find.
- θ is the angle of diffraction, which is 0.046 degrees or 0.046*(π/180) radians.

First, we rearrange the equation to solve for d: d = nλ / (2 sin θ).

Substituting the given values, we get: d = (1 * 6000*10^-10 m) / (2 * sin(0.046*(π/180))) ≈ 3.88*10^-6 m.

The velocity of the ultrasonic waves (v) can be calculated using the formula v = fλ, where f is the frequency of the ultrasonic waves. Given that the frequency is 2 MHz or 2*10^6 Hz, we substitute the values into the formula to get: v = 2*10^6 Hz * 3.88*10^-6 m ≈ 7.76 m/s.

Therefore, the velocity of the ultrasonic waves in the liquid is approximately 7.76 m/s.

Question

To calculate the velocity of ultrasonic waves in the liquid, we can use the Bragg's law of diffraction, which states that nλ = 2d sin θ, where:

- n is the order of diffraction, which is 1 in this case.
- λ is the wavelength of the light, which is 6000 Å or 6000*10^-10 m.
- d is the spacing between the layers in the crystal, which is what we're trying to find.
- θ is the angle of diffraction, which is 0.046 degrees or 0.046*(π/180) radians.

First, we rearrange the equation to solve for d: d = nλ / (2 sin θ).

Substituting the given values, we get: d = (1 * 6000*10^-10 m) / (2 * sin(0.046*(π/180))) ≈ 3.88*10^-6 m.

The velocity of the ultrasonic waves (v) can be calculated using the formula v = fλ, where f is the frequency of the ultrasonic waves. Given that the frequency is 2 MHz or 2*10^6 Hz, we substitute the values into the formula to get: v = 2*10^6 Hz * 3.88*10^-6 m ≈ 7.76 m/s.

Therefore, the velocity of the ultrasonic waves in the liquid is approximately 7.76 m/s.

Knowee AI · Accepted Answer

To calculate the velocity of ultrasonic waves in the liquid, we can use the Bragg's law of diffraction, which states that nλ = 2d sin θ, where:

- n is the order of diffraction, which is 1 in this case.
- λ is the wavelength of the light, which is 6000 Å or 6000*10^-10 m.
- d is the spacing between the layers in the crystal, which is what we're trying to find.
- θ is the angle of diffraction, which is 0.046 degrees or 0.046*(π/180) radians.

First, we rearrange the equation to solve for d: d = nλ / (2 sin θ).

Substituting the given values, we get: d = (1 * 6000*10^-10 m) / (2 * sin(0.046*(π/180))) ≈ 3.88*10^-6 m.

The velocity of the ultrasonic waves (v) can be calculated using the formula v = fλ, where f is the frequency of the ultrasonic waves. Given that the frequency is 2 MHz or 2*10^6 Hz, we substitute the values into the formula to get: v = 2*10^6 Hz * 3.88*10^-6 m ≈ 7.76 m/s.

Therefore, the velocity of the ultrasonic waves in the liquid is approximately 7.76 m/s.

The wavelength of light transmitted through a liquid is 6000 Å.The first order angle of diffraction is 0.046o. Calculate thevelocity of ultrasonic waves in the liquid. The frequency of theultrasonic waves produced by the transducer is 2MHz

Question

Solution

Similar Questions

Upgrade your grade with Knowee