What is the inverse function of f(x) = x/8 + x + 2?

To find the inverse of the function f(x) = x/8 + x + 2, we first replace f(x) with y. This gives us:

y = x/8 + x + 2

Next, we swap x and y:

x = y/8 + y + 2

We then solve for y:

x - 2 = y/8 + y

Multiply everything by 8 to get rid of the fraction:

8x - 16 = y + 8y

Combine like terms:

8x - 16 = 9y

Finally, solve for y:

y = (8x - 16) / 9

So, the inverse function of f(x) = x/8 + x + 2 is f^-1(x) = (8x - 16) / 9.