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Use the quadratic formula to solve 4x 2 = 11x – 5.The solution is:x=−11±41−−√8𝑥=−11±418 x=11±41−−√8𝑥=11±418 x=−11±201−−−√8𝑥=−11±2018 x=11±201−−−√8

Question

Use the quadratic formula to solve 4x 2 = 11x – 5.The solution is:x=−11±41−−√8𝑥=−11±418 x=11±41−−√8𝑥=11±418 x=−11±201−−−√8𝑥=−11±2018 x=11±201−−−√8

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Solution

The given equation is 4x^2 = 11x - 5.

First, we need to rearrange the equation into standard quadratic form ax^2 + bx + c = 0.

So, 4x^2 - 11x + 5 = 0.

Now, we can apply the quadratic formula which is x = [-b ± sqrt(b^2 - 4ac)] / (2a).

Here, a = 4, b = -11, and c = 5.

Substituting these values into the quadratic formula gives:

x = [11 ± sqrt((-11)^2 - 445)] / (2*4) x = [11 ± sqrt(121 - 80)] / 8 x = [11 ± sqrt(41)] / 8

So, the solutions of the equation 4x^2 = 11x - 5 are x = (11 + sqrt(41)) / 8 and x = (11 - sqrt(41)) / 8.

This problem has been solved

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