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Gold in 20 times as heavy as water and copper is 10 times as heavy as water. In what ratio these two metals be mixed so that the alloy is 13 times as heavy as water is Options : A] 2:7 B] 3:7 C] 1:2 D] 2:3

Question

Gold in 20 times as heavy as water and copper is 10 times as heavy as water. In what ratio these two metals be mixed so that the alloy is 13 times as heavy as water is

Options : A] 2:7 B] 3:7 C] 1:2 D] 2:3

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Solution

This problem can be solved using the method of Allegation, which is a rule of mixture to find the ratio in which two or more ingredients at the given price must be mixed to produce a mixture of a desired price.

The mean price is 13 (the weight of the alloy), the cheaper price is 10 (the weight of copper), and the costlier price is 20 (the weight of gold).

The formula for Allegation is:

(Costlier price - Mean price) : (Mean price - Cheaper price)

Substituting the given values into the formula, we get:

(20 - 13) : (13 - 10) = 7 : 3

So, the ratio in which gold and copper should be mixed is 7:3.

Therefore, the correct answer is option B] 3:7.

This problem has been solved

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