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A and B are two alloys of gold and copper prepared by mixing metals in ratios 7 : 2 and 7 : 11 respectively. If equal quantities of the alloys are melted to form a third alloy C, the ratio of gold and copper in C will be?Options7 : 59 : 55 : 75 : 9

Question

A and B are two alloys of gold and copper prepared by mixing metals in ratios 7 : 2 and 7 : 11 respectively. If equal quantities of the alloys are melted to form a third alloy C, the ratio of gold and copper in C will be?Options7 : 59 : 55 : 75 : 9

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Solution

To solve this problem, we need to follow these steps:

  1. First, let's assume that the equal quantity of alloys A and B that are mixed together is 1 unit each.

  2. In alloy A, the ratio of gold to copper is 7:2. This means that in 1 unit of alloy A, there is 7/9 units of gold and 2/9 units of copper.

  3. In alloy B, the ratio of gold to copper is 7:11. This means that in 1 unit of alloy B, there is 7/18 units of gold and 11/18 units of copper.

  4. When we mix equal quantities of alloys A and B to form alloy C, the quantity of gold in alloy C will be the sum of the quantities of gold in alloys A and B. Similarly, the quantity of copper in alloy C will be the sum of the quantities of copper in alloys A and B.

  5. Therefore, the quantity of gold in alloy C is 7/9 + 7/18 = 14/18 + 7/18 = 21/18 = 7/6 units.

  6. The quantity of copper in alloy C is 2/9 + 11/18 = 4/18 + 11/18 = 15/18 = 5/6 units.

  7. Therefore, the ratio of gold to copper in alloy C is 7/6 : 5/6 = 7:5.

So, the correct option is 7:5.

This problem has been solved

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