redict the output of following Java programclass Test extends Exception {}class Main { public static void main(String args[]) { try { throw new Test(); } catch (Test t) { System.out.println("Got the Test Exception"); } finally { System.out.println("Inside finally block "); } }}OptionsGot the Test Exception Inside finally blockInside finally blockCompiler ErrorGot the Test Exception
Question
redict the output of following Java programclass Test extends Exception {}class Main { public static void main(String args[]) { try { throw new Test(); } catch (Test t) { System.out.println("Got the Test Exception"); } finally { System.out.println("Inside finally block "); } }}OptionsGot the Test Exception Inside finally blockInside finally blockCompiler ErrorGot the Test Exception
Solution
The output of the Java program will be:
Got the Test Exception Inside finally block
Here's the step by step explanation:
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The program starts with the definition of a class named Test that extends the Exception class. This means that Test is a custom exception.
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The main method of the Main class is where the execution of the program begins.
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Inside the main method, a try-catch-finally block is defined.
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In the try block, the program throws a new instance of the Test exception.
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The catch block catches this specific exception (Test t). When this happens, it prints out the string "Got the Test Exception".
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Regardless of whether an exception was thrown and caught, the finally block will always execute. This block prints out the string "Inside finally block ".
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Therefore, the output of the program will be the print statements from both the catch and the finally blocks.
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