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Select the correct answerWhat is the output of the Java code with FINALLY block and RETURN statement?public class ExceptionTest6 { static void show() { try { System.out.println("inside TRY"); return; } finally { System.out.println("inside FINALLY"); } } public static void main(String[] args) { show(); }}Optionsinside TRYinside FINALLYCompiler errorinside TRYinside FINALLY

Question

Select the correct answerWhat is the output of the Java code with FINALLY block and RETURN statement?public class ExceptionTest6 { static void show() { try { System.out.println("inside TRY"); return; } finally { System.out.println("inside FINALLY"); } } public static void main(String[] args) { show(); }}Optionsinside TRYinside FINALLYCompiler errorinside TRYinside FINALLY

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Solution

The correct answer is "inside TRY" followed by "inside FINALLY".

Here's the step by step explanation:

  1. The show() method is called from the main method.
  2. Inside the show() method, the code inside the try block is executed first. It prints "inside TRY" and then encounters a return statement.
  3. Normally, a return statement would end the method execution and control would go back to the calling method. However, if a finally block is present, it gets executed before the method ends, no matter what.
  4. So, after the try block, the finally block is executed and "inside FINALLY" is printed.
  5. After the finally block, the method ends and control goes back to the main method.

So, the output of the code will be:

inside TRY
inside FINALLY

This problem has been solved

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