An enzyme-catalysed reaction is assembled by combining 0.6 mL water, 0.6 mL of 2 mM substrate, 1.3 mL buffer and 0.5 mL enzyme. What is the substrate concentration in the reaction? 0.4 mM 0.5 mM 0.6 mM 0.8 mM 1.0 mM
Question
An enzyme-catalysed reaction is assembled by combining 0.6 mL water, 0.6 mL of 2 mM substrate, 1.3 mL buffer and 0.5 mL enzyme. What is the substrate concentration in the reaction? 0.4 mM 0.5 mM 0.6 mM 0.8 mM 1.0 mM
Solution
To calculate the substrate concentration in the reaction, we need to use the formula for dilution: C1V1 = C2V2, where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.
Here, the initial concentration of the substrate (C1) is 2 mM and the initial volume of the substrate (V1) is 0.6 mL. The final volume (V2) is the total volume of the reaction, which is the sum of the volumes of all components: 0.6 mL (water) + 0.6 mL (substrate) + 1.3 mL (buffer) + 0.5 mL (enzyme) = 3 mL.
We can now substitute these values into the formula and solve for C2, the final concentration of the substrate:
2 mM * 0.6 mL = C2 * 3 mL
1.2 mM = C2 * 3 mL
C2 = 1.2 mM / 3 mL = 0.4 mM
So, the substrate concentration in the reaction is 0.4 mM.
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