An enzyme-catalyzed reaction was carried out with the substrate concentration initially a thousand times greater than the Km for that substrate. After 21 seconds, 1% of the substrate had been converted to product, and the amount of product formed in the reaction mixture was 12 mmol. If, in a separate experiment, 1/2 times as much enzyme was used. How long (sec) would it take for the same amount (12 mmol) of product to be formed?

n enzyme-catalysed reaction was carried out and after 9 minutes the amount of product formed in the reaction mixture was 12mM. If, in a separate experiment, one-third as much enzyme was used, how long would it take for the same amount (12mM) of product to be formed?Selected Answer: [None Given]Answers: A. 1.5min.B. 24min.C. 27min.D. 13.5min.E. 3.0min

An enzyme-catalysed reaction is assembled by combining 0.6 mL water, 0.6 mL of 2 mM substrate, 1.3 mL buffer and 0.5 mL enzyme. What is the substrate concentration in the reaction? 0.4 mM 0.5 mM 0.6 mM 0.8 mM 1.0 mM

In reaction 1, 12g of reactants were converted to products in 30 seconds. In reaction 2, 200g of reactants were converted to products in 8 minutes. Which reaction happened at the faster rate?

The active ingredient in an aqueous preparation has an initial concentration of 6.2*10-3 g/mL. After 4 months the concentration was determined by analysis to be 5 *10-3 g/mL. The product is known to be ineffective after it has decomposed to 50% of its original concentration. Assuming the decomposition follows first order kinetics, calculate how long it will take to reach 50% of the original concentration. Answer in months log C = log C0 - (k1/2.303 )* t t1/2 = 0.693/k

t takes 0.4 minutes for an enzyme-controlled reaction to occur.Calculate the rate of reaction per minute.(How many reactions will occur in a minute? Do not include units in your answer.)Give your answer to 1 decimal place.