An atom of an element A has three electrons in its outermost orbit and that of B has six electrons in its outermost orbit. The formula of the compound between these two will be :A A3B6 B A2B3 C A3B2 D A2B
Question
An atom of an element A has three electrons in its outermost orbit and that of B has six electrons in its outermost orbit. The formula of the compound between these two will be :A A3B6 B A2B3 C A3B2 D A2B
Solution
The formula of the compound can be determined by the cross method, which is based on the valency of the elements.
Step 1: Identify the valency of each element. The valency of an element is determined by the number of electrons in its outermost orbit. In this case, element A has 3 electrons in its outermost orbit, so its valency is 3. Element B has 6 electrons in its outermost orbit, so its valency is 6.
Step 2: Apply the cross method. This involves crossing over the valencies of the two elements to form the formula of the compound.
So, the formula of the compound would be A6B3. However, this formula can be simplified by dividing the subscripts by their highest common factor, which is 3.
So, the simplified formula of the compound would be A2B.
Therefore, the correct answer is D: A2B.
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